Union Public Service Commission has released the latest job notification for the Scientist-B (Mechanical) vacancy. Interested candidates can apply before the last date. Check more details on the Union Public Service Commission 2024 job vacancy.
Union Public Service Commission has released an employment notification for the recruitment of Scientist-B (Mechanical) Vacancy. More details about the recruitment are provided below:
Post Name: Scientist-B (Mechanical) in National Test House, Department of Consumer Affairs, Ministry of Consumer Affairs, Food and Public Distribution
Posts: 1
Location: All India
Salary: As Per UPSC Norms
Last Date: 11/04/2024
Age: Not Mentioned
To apply for the post of Scientist-B (Mechanical) at Union Public Service Commission, the candidate should have completed Master’s Degree in Physics from a recognized University/ Institute altogether, or Bachelor of Engineering or Bachelor of Technology in Mechanical Engineering/
Metallurgical Engineering from a recognized University or Institute altogether.
Candidates may apply online for the above positions through the website https://www.upsconline.nic.in/ up to 11th April 2024
Disclaimer: Provided by the Union Public Service Commission
The UPSC conducts various examinations in accordance with the Rules of examination as notified by the Government of India in a just, fair and impartial manner for making a merit based selection and recommendation of candidates for various Group A and Group B Services of the Govt. of India.
Q. What is the last date to apply for UPSC Recruitment ?
A. The last date to apply for UPSC Recruitment is 11th April, 2024.
Q. What are the total number of posts vacant for UPSC Recruitment ?
A. The total number of posts vacant for UPSC Recruitment is 1.
Q. What is the job location for UPSC Recruitment ?
A. The job location for UPSC Recruitment is all India.